Wagering Strategy 102: Betting In 2-Day Finals

Make sure to check out Wagering Strategy 101: How To Bet In Final Jeopardy! as well!

Preamble

I originally published most of this guide in May 2012, shortly after becoming part of the writing team here at The Jeopardy! Fan. However, with the preponderance of two-game total-point matches in modern Jeopardy, I think elevating this guide up to “page” status is important.

The math is more difficult, and the stakes (in both glory and money) are higher. Thus, it’s important to have practiced this beforehand! Mistakes have been made here, even by some of the best players in the show’s history.

What’s Happening?

In a two-game total-point final, the final scores after Game 1 are locked in. Then, scores are reset to zero for the start of Game 2, and at the conclusion of Game 2, Game 1’s scores are added back. This makes the math more difficult than you’re used to, because you have an earlier game to take into account!

Day 1’s Final Jeopardy

This is pretty simple: Because there are still 61 clues to play after this, there’s still an opportunity to make up for anything lost. Thus, I would bet this as if it was a Daily Double that all three players get to play.

I should also note that Final Jeopardy clues do tend to be slightly more difficult than Daily Doubles in-game; I would definitely adjust your bet sizing accordingly, thinking that the clue would be more difficult than a regular Daily Double.

Day 2’s Final Jeopardy

Here’s where it gets fun and interesting. Because the math is more difficult, I will explain everything from “first principles” (if you’ll excuse the calculus term here). Much like “Wagering 101”, I’d recommend practicing until you figure everything out within 4 minutes or less.

Example 1: 2000 Tournament of Champions Final

Using the 2000 Tournament of Champions final as my first example, I will walk through a couple of situations.

The scores after Day 1:

Robin Carroll $8,000
Jeremy Bate $7,000
Steve Fried $4,500

The scores going into Final Jeopardy on Day 2:

Robin Carroll $4,600
Jeremy Bate $1,500
Steve Fried $7,000

Your first step should be to figure out who has the advantage.

To determine who can win with a correct response and a sufficient wager, double everybody’s Day 2 score and then add that to their Day 1 score.

In our example:

Robin: 4,600 * 2 = 9,200 + 8,000 = 17,200
Jeremy: 1,500 * 2 = 3,000 + 7,000 = 10,000
Steve: 7,000 * 2 = 14,000 + 4,500 = 18,500

In this example, Steve controls his destiny.

Additionally, you should determine if the player with the advantage has a runaway. Add that player’s Day 1 and Day 2 scores together to do this. The leader has a runaway if it’s more than second place’s doubled score. If it’s not, then there is no runaway.

In this example:

Steve: 7,000 + 4,500 = 11,500; that is less than Robin’s 17,200; thus, he does not have a runaway.

Your next priority should be to determine the leader’s optimum wager. This should be the wager that wins the tournament by $1 if everybody answers correctly and the two trailing players bet everything.

Therefore, Steve should wager to ensure that his two-day total is $17,201.

To arrive at this wager, take that target total, subtract your first-day total, and then subtract your current score going into Final Jeopardy.

Therefore, Steve’s optimum wager is:

17,201 – 4,500 = 12,701 – 7,000 = 5,701

From here, the other two players must realize that the only way to lose is if the leader misses Final Jeopardy. Therefore, they should wager to best take advantage of this situation after ensuring they have covered any player behind them.

As Robin is in second place, she must assume that Steve will miss and Jeremy will get the question correct and wager everything.

In our situation, if Steve misses Final Jeopardy, he will fall to:

7,000 – 5,701 = 1,299 + 4,500 = 5,799

This bodes well for Robin, as her Day 1 total is 8,000. However, she still needs to worry about Jeremy behind her.

If Robin wagers nothing, her score sits at:

4,600 + 0 = 4,600 + 8,000 = 12,600

This is higher than Jeremy’s maximum possible total of $10,000. Therefore, Robin needs to ensure her score does not fall below $10,001.

If you can’t afford to fall below a certain number, arrive at it as follows: Take the score you would finish with if you wagered nothing and subtract the target score. Robin’s optimum wager is:

12,600 – 10,001 = 2,599

In Jeremy’s situation, he can only win if Robin makes a wagering blunder. As most wagering blunders from second-placed contestants consist of wagering either everything or nearly everything, Jeremy should wager to make certain he does not fall behind Robin’s score from the first game. A good target score for Jeremy would be $8,001 (though wagering $0 in this situation is also quite defensible).

Jeremy’s optimum wager is calculated the same as Robin’s:

1,500 + 0 = 1,500 + 7,000 = 8,500 – 8,001 = 499

In summary, the thought process should be:

  1. Determine who is leading by doubling everybody’s second-day scores and adding that total to the first day.
  2. Determine what the leader’s optimum wager is.
  3. Determine the 2nd-place player’s optimum wager based on the score of 3rd place and the leader’s wager.
  4. Determine what the trailer’s optimum wager is based on the wagers of the players ahead.

One important note: Bet the maximum amount you can without jeopardizing your chances of victory in this situation. This may work in your favor if the player in front of you makes a mathematical error.

Returning to our example, here’s what the players wagered:

Robin: $4,600
Jeremy: $1,500
Steve: $5,701

And here’s how the tournament turned out:

Robin: $4,600 – $4,600 = $0 + $8,000 = $8,000
Jeremy: $1,500 – $1,500 = $0 + $7,000 = $7,000
Steve: $7,000 – $5,701 = $1,299 + $4,500 = $5,799

Here’s how the tournament would have turned out with optimum wagers:

Robin: $4,600 – $2,599 = $2,001 + $8,000 = $10,001
Jeremy: $1,500 – $499 = $1,001 + $7,000 = $8,001
Steve: $7,000 – $5,701 = $1,299 + $4,500 = $5,799

Steve was the only player of the three to wager properly. Holding everything else constant, Jeremy would have won the tournament had he wagered less. Robin was very lucky that her wagering blunder did not come back to haunt her.



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Are you going on the show and looking for information about how to bet in Final Jeopardy? Check out my Betting Strategy 101 page. If you want to learn how to bet in two-day finals, check out Betting Strategy 102. In case the show uses a tournament with wild cards in the future, there is also a strategy page for betting in tournament quarterfinals.

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Example 2: 2003 Tournament of Champions Final

Here is one more wagering scenario for you to ponder:

2003 Tournament of Champions Final:

Scores after Day 1:

Mark Dawson 22,400
Brian Weikle 15,000
Eric Floyd 7,300

The scores going into Final Jeopardy on Day 2:

Brian 22,000
Mark 17,200
Eric 6,200

Who’s leading?

Brian: 22,000 * 2 = 44,000 + 15,000 = 59,000
Mark: 17,200 * 2 = 34,400 + 22,400 = 56,800
Eric: 6,200 * 2 = 12,400 + 7,300 = 19,700

Does Brian have a runaway?

Brian: 22,000 + 15,000 = 37,000; less than Mark’s 56,800, therefore not a runaway.

We then determine Brian’s optimum wager first.

Target score: $56,801

56,801 – 15,000 = 41,801 – 22,000 = 19,801

Now, we move on to Mark.

If Brian is wrong, he falls to:

22,000 – 19,801 = 2,199 + 15,000 = 17,199

Since this total and Eric’s maximum possible total are below Mark’s Day 1 score of 22,000, the optimal wager is to bet everything, get the question right, and hope that Brian either misses the Final or shanks the wager.

As for Eric, he can not catch Mark, but he can catch Brian if Brian misses. Eric’s minimum target score becomes $17,200. His optimum wager is therefore at least:

17,200 – 7,300 = 9,900 – 6,200 = 3,700

However, as with Mark, Eric might as well bet everything as he needs to be correct to catch Brian, and he can’t catch Mark no matter what happens.

Here’s what happened, in case you don’t know:

Brian: $22,000 + $19,601 = $41,601 + $15,000 = $56,601
Mark: $17,200 + $17,200 = $34,400 + $22,400 = $56,800
Eric: $6,200 + $6,199 = $12,399 + $7,300 = $19,699

What happened here? Brian accidentally wrote the 8 in 56,800 as a second 6 when he was doing his math. The mistake ended up being a nearly $200,000 one, and it brings this suggestion:

Brian was in a situation where a wrong answer would not have garnered him victory, and his destiny for 2nd or 3rd would have been controlled solely by whether Eric was correct or not (We’ll assume that Eric knows how to wager —this is the Tournament of Champions final, after all.) If you’re in this situation where you’re guaranteed to lose if you miss Final Jeopardy, it’s not a bad idea to add $1,000 or so to your wagered total, just in case.

In Conclusion

The math is harder, but a skillful wager can be incredibly rewarding! Again, I recommend practicing with situations until you figure out the numbers within 4 minutes. Good luck!

If you have any feedback regarding this guide, the author’s contact information can be found here.


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